3x^2+15x+16=0

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Solution for 3x^2+15x+16=0 equation: 



3x^2+15x+16=0

a = 3; b = 15; c = +16;
Δ = b2-4ac
Δ = 152-4·3·16
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{33}}{2*3}=\frac{-15-\sqrt{33}}{6}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{33}}{2*3}=\frac{-15+\sqrt{33}}{6}
$

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